2h+3h+4h^2=84h=

Solution for 2h+3h+4h^2=84h= equation:

2h+3h+4h^2=84h=

We move all terms to the left:

2h+3h+4h^2-(84h)=0

We add all the numbers together, and all the variables

4h^2-79h=0

a = 4; b = -79; c = 0;
Δ = b2-4ac
Δ = -792-4·4·0
Δ = 6241
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6241}=79$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-79)-79}{2*4}=\frac{0}{8}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-79)+79}{2*4}=\frac{158}{8}
=19+3/4
$